[2x+3(x+1)]=x+20

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Solution for [2x+3(x+1)]=x+20 equation:


Simplifying
[2x + 3(x + 1)] = x + 20

Reorder the terms:
[2x + 3(1 + x)] = x + 20
[2x + (1 * 3 + x * 3)] = x + 20
[2x + (3 + 3x)] = x + 20

Reorder the terms:
[3 + 2x + 3x] = x + 20

Combine like terms: 2x + 3x = 5x
[3 + 5x] = x + 20

Remove brackets around [3 + 5x]
3 + 5x = x + 20

Reorder the terms:
3 + 5x = 20 + x

Solving
3 + 5x = 20 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
3 + 5x + -1x = 20 + x + -1x

Combine like terms: 5x + -1x = 4x
3 + 4x = 20 + x + -1x

Combine like terms: x + -1x = 0
3 + 4x = 20 + 0
3 + 4x = 20

Add '-3' to each side of the equation.
3 + -3 + 4x = 20 + -3

Combine like terms: 3 + -3 = 0
0 + 4x = 20 + -3
4x = 20 + -3

Combine like terms: 20 + -3 = 17
4x = 17

Divide each side by '4'.
x = 4.25

Simplifying
x = 4.25

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